The molarity of a solution obtained by mixing 750 mL of 0.5(M) HCI with 250 mL of 2(M) HCI will be

Options

A. 0.975(M)
B. 1.00(M)
C. 0.875(M)
D. 1.75(M)

Explanation

750mL 0.5(M) HCl contain `(0.5)/(1000)xx750=0.375mol`
of HCl and 250mL of 2(M) HCl contains `2/(1000)xx250`=0.5 mol of HCl. Volume of the resulting solution = 750 + 250 = 1000mL . Total number of moles of HCl in the solution = 0.375 + 0.5 = 0.875 mol `:.` Molarity of the resulting solution = 0.875(M)