The percentage of pyridine `(C_5H_5N)` that forms pyridinium ion `(C_5H_5N^+H)` in a 0.10(M) aqueous pyridine solution `(K_b)` for `C_5H_5N=107xx10^(9))` is

Options

A. `0.0060%`
B. `0.013%`
C. 0.0077
D. 0.016

Explanation

`prop=sqrt((K_b)/(c))=sqrt((1.7xx10^(-9))/(0.1))=1.3xx10^(-4)` `:.` amount of produced pyridinium ion
`=0.1xxprop=0.1xx1.3xx10^(-4)=1.3xx10^(-5)`
% amount of pyridine
`=(0.1xx1.3xx10^(-4))/(0.1)xx100=1.3xx10^(-2)%=0.013%`