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25 mL, 0.2 M Ca(OH)2 is neutralised by 1...

25 mL, 0.2 M `Ca(OH)_2` is neutralised by 10 mL of 1 M HCl. then pH of resulting solution is-

A

1.37

B

9

C

12

D

7

Text Solution

Verified by Experts

Number of millimoles of base ( i.e, `Ca(OH)_2`)
`=N_1V_1=2xxM_1xxV_1=2xx0.2xx25=10`
number of millimoles of acid (i.e HCl)=`N_2V_2`
`=10xx1=10` As, no. of millimoles of acid = no. of millimoles of base, so acid is completely neutralised by base forming a neutral solution.
`:.` pH of the resulting solution=7
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