`K_(sp)` of `CaSO_4*5H_2O` is `9xx10^(-6)`, find the volume for 1g of `CaSO_4` (M.mass=136)

Options

A. 2.45 litre
B. 5.1 litre
C. 4.52 litre
D. 3.2 litre

Explanation

`CaSO_4(s) `K_(sp)=S^2=9xx10^(-6)`
`S=3xx10^(-3)mol*L^(-1)`
solubility in `g*L^(-1)`=molecular mass `xx` S
`136xx3xx10^(-3)=408xx10^(-3)g*L^(-1)`
`408xx10^(-3)g` of `CaSO_4` is present in 1 litre.
1g of `CaSO_4` is present `1/(408xx10^(-3))=2.45` litre.