Give reason :
On the basis of `E^(@)` values, `O_(2)` gas should be liberated at anode. But it is `Cl_(2)` gas which is liberated in the electrolysis of aqueous `NaCl.`

Explanation

From the standard oxidising potential, it is clear that oxygen gas should be liberated at anode, but its rate, of production is very low. In order to increase the rate we increase the voltage of external battery because of which chloride ions get oxidised easily and `Cl_(2)`, gas liberates at anode.