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Lambda(m)^(@) for NaCl, HCl and NaAc are...

`Lambda_(m)^(@)` for NaCl, HCl and NaAc are 126.4, 425.9 and `"91 S.cm"^(2)."mol"^(-1)` respectively. Calculate `Lambda^(@)` for Hac.

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`Lambda_(m(Hac))^(@)=lambda_(H^(+))^(@)+lambda_(Ac^(-))^(@)`
`=lambda_(H^(+))^(@)+lambda_(Cl^(-))^(@)+lambda_(Ac^(-))^(@)+lambda_(Na^(+))^(@)-lambda_(Cl^(-))^(@)-lambda_(Na^(+))^(@)`
`=Lambda_(m(HCl))^(@)+Lambda_(m(NaAc))^(@)-Lambda_(m(NaCl))^(@)`
`=425.9+91.0-126.4=390.5" S.cm"^(2)."mol"^(-1)`
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