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A solution of CuSO(4) is electrolysed fo...

A solution of `CuSO_(4)` is electrolysed for 10 minutes with a current of 1.5 A. What is the mass of copper deposited at the cathode?

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Quantity of electricity = current `xx` time
`=1.5Axx600s=900C`
and time, `t=10xx60=600s`. According to the reaction: `Cu^(2+)(aq)+2e =Cu(s), 2F` or `2xx96500C` of electricity deposit 1 mol or 63.5 g of Cu. For 900C, mass of Cu deposited `=("63.5 g.mol"^(-1)xx900C)/(2xx96500" C.mol"^(-1))=0.2961g`
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