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Between (a) 0.01 (M) H(2)SO(4) and (b) 0...

Between (a) 0.01 (M) `H_(2)SO_(4)` and (b) 0.01 (M) `H_(3)PO_(4)` solution, which one has higher equivalent conductivity? (Assume that, each solution has the same specific conductance and the degree of dissociation of each acid is equal to unity).

Text Solution

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`"0.01 (M) "H_(2)SO_(4)-=0.02(N)" "H_(2)SO_(4) and " 0.01 (M)"`
`H_(3)PO_(4)=0.03(N) H_(3)PO_(4)`.
Applying the reaction `Lambda=(kappaxx1000)/(N)` to calculate `Lambda` gives
`Lambda(H_(3)SO_(4))( kappa xx 1000)/(0.02)= kappa xx50000`
`Lambda(H_(3)PO_(4))(kappa xx1000)/(0.03)=kappa xx333.333xx10^(2) = kappa xx33333.3`
As `kappa` for each solution is the same, the value of `Lambda` for 0.01 M `H_(2)SO_(4)` solution will be greater than that for 0.1 M `H_(3)PO_(4)` solution.
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