Home
Class 12
CHEMISTRY
The formal potential of Fe^(3+)|Fe^(2+) ...

The formal potential of `Fe^(3+)|Fe^(2+)` in a sulphuric acid and phosphoric and mixture `(E^(@)=+0.61V)` is much lower than the standard potential `(E^(@)=+0.77V)`. The is due to -

A

formation of the species `[FeHPO_(4)]^(+)`

B

lowering of potential upon complexation

C

formation of the species `[FeSO_(4)]^(+)`

D

high acidity of the medium

Text Solution

Verified by Experts

The correct Answer is:
A, B, D

Due to the formation of different complexes, concentration of `Fe^(3+)` decreases. Thus the formal potential of `Fe^(3+)|Fe^(2+)` is lower than its standard potential.
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    CHHAYA PUBLICATION|Exercise ENTRANCE QUESTION BANK (JEE-MAIN)|10 Videos
  • ELECTROCHEMISTRY

    CHHAYA PUBLICATION|Exercise ENTRANCE QUESTION BANK (NEET)|23 Videos
  • ELECTROCHEMISTRY

    CHHAYA PUBLICATION|Exercise ADVANCED LEVEL NUMERICAL BANK|38 Videos
  • D - AND F - BLOCK ELEMENTS

    CHHAYA PUBLICATION|Exercise PRACTICE SET 8 (Answer the following questions)|10 Videos
  • ENVIRONMENTAL CHEMISTRY

    CHHAYA PUBLICATION|Exercise PRACTICE SET 14(Answer the following questions)|6 Videos

Similar Questions

Explore conceptually related problems

The standard electrode potential of Cu^(2+)|Cu half cell is +0.34V . What does it mean?

Determine reduction potential of the given electrode reaction at 25^(@)Cl Cu^(2+)(0.1M, aq)+2erarrCu(s). The standard reduction potential of Cu^(2+)|Cu system =+0.34V .

Given the standard half - cell potentials (E^(@)) of the following as : Zn rarr Zn^(2+)+2e , E^(@)=+0.76V Fe rarr Fe^(2+)+2e, E^(@)=0.41V The the standard EMF of the cell with the reaction Fe^(2+)+Zn rarr Zn^(2+)+Fe is -

For the half - cell Fe^(3+), Fe^(2+)|Pt , the concentration of Fe^(2+) and Fe^(3+) ions are 0.1 and 0.01 (M) respectively. Determine the reduction potential of the half - cell at 25^(@)C . Given : E_(Fe^(3+), Fe^(2+)|Pt)^(@)=+0.77V

Why standard reduction potential (E^(0)) of Zn^(2+)|Zn system is more negative than expected ?

Assume than an electric field vec(E ) = 30 x^(2)hat(i) exists in space. Then the potential difference V_(A) - V_(O) , where V_(O) is the potential at the origin and V_(A) the potential at x = 2 m is

A solution contains Fe^(3+), Fe^(2+) and I^(-) ions. This solution was treated with iodine at 35^(@)C . E_(Fe^(3+)|Fe^(2+))^(@)=+0.77V and E_(I_(2)|2I^(-))^(@)=+-.536V . The favourable redox reaction is -

The standard reduction potential of Zn-electrode is -0.76V. The standard oxidation potential of the electrode will be ______________.

Consider the following cell reaction Znabs(Zn^(2+)(1M)) abs(Cd^(+2)(1M))Cd.Give the cell reaction and calculate the standard cell potential. (E^0)_((Zn^(2+))/(Zn)=-0.76V , (E^0)_((Cd^(2+))/(Cd)=0.40V