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At a particular temperature, the ratio o...

At a particular temperature, the ratio of equivalent conductance to specific conductance of a 0.01 N `NaCl` solution is -

A

`10^(5)cm^(3)`

B

`10^(3)cm^(3)`

C

`10cm^(3)`

D

`10^(5)cm^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`Lambda=kappa xx(1000)/(C)=kappa xx(1000)/(0.01)`
`therefore (Lambda)/(kappa)=(1000)/(0.01)=10^(5)cm^(3).g-"equiv"^(-1)`
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