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Given : E(Cr^(3+)|Cr)^(@)=-0.74V, E(MnO(...

Given : `E_(Cr^(3+)|Cr)^(@)=-0.74V, E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V`
`E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V, E_(Cl|Cl^(-))^(@)=1.36V`
Based on the data, strongest oxidising agent -

A

`Cl^(-)`

B

`Cr^(3+)`

C

`Mn^(2+)`

D

`MnO_(4)^(-)`

Text Solution

Verified by Experts

The correct Answer is:
D
Lower is the value of the standard reduction potential, higher is the tendency to be oxidised and vice-versa. Among the given system, `Cr^(3+)|Cr` has the lowest `E^(@)` value. Thus `MnO_(4)^(-)` has the highest tendency to be reduced and hence acts as a strong oxidising agent.
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