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Resistance of 0.2 M solution of an elect...

Resistance of 0.2 M solution of an electrolyte is `50Omega`. The specific conductance of the solutions is `"1.4 S.m"^(-1)`. The resistance of 0.5 M solution of the same electrolyte is `280Omega`. The molar conductivity of 0.5 M solution of the electrolyte is `"S.m"^(2)."mol"^(-1)`-

A

`5xx10^(2)`

B

`5xx10^(-4)`

C

`5xx10^(-3)`

D

`5xx10^(3)`

Text Solution

Verified by Experts

The correct Answer is:
B
`kappa =(1)/(R)xx(l)/(A)`
`"for 0.2(M) solution, 1.4 "=(1)/(50)xx((l)/(A))" "therefore (l)/(A)=70m^(-1)`
`"for 0.5 (M) solution, "kappa =(1)/(280)xx70="0.25 ohm"^(-1)."m"^(-1)`
`Lambda_(m)=(kappa)/(M)=-0.25xx(1)/(0.5)="0.5 ohm"^(-1).m^(-1)."L.mol"^(-1)`
`=0.5xx10^(-3)"ohm"^(-1).m^(-2)."mol"^(-1)`
`=5xx10^(-4)"S.m"^(2)."mol"^(-1)`
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