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Two faraday of electricity is passed thr...

Two faraday of electricity is passed through a solution of `CuSO_(4)`. The mass of copper deposited at the cathode is (at. Mass of Cu = 63.5u) -

A

0 g

B

63.5 g

C

2 g

D

127 g

Text Solution

Verified by Experts

The correct Answer is:
B
`Cu^(2+)(aq)+2e rarr Cu(s)`
`therefore " 2F electricity "-="1 mol Cu"-=" 63.5gCu"`
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