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Electode potential of hydrogen electrode...

Electode potential of hydrogen electrode is 18 mV, then `[H^(+)]` is -

A

0.2 M

B

1 M

C

2 M

D

5 M

Text Solution

Verified by Experts

The correct Answer is:
C
Applying Nernst equation,
`E_(H^(+)|H_(2))=E_(H^(+)|H_(2))^(0)-(0.0591)/(1)log.(1)/([H^(+)])`
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