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|{:("Electolyte",KCl,KNO(3),HCl,NaOAc,Na...

`|{:("Electolyte",KCl,KNO_(3),HCl,NaOAc,NaCl),(underset(("S.cm"^(2)."mol"^(-1)))(Lambda^(oo)),149.9,145.0,426.2,91.0,126.5):}|`
Calculate `Lambda_(HOAc)^(oo)("in S.cm"^(2)."mol"^(-1))` using appropriate molar conductances of the electrolytes listed above at infinite dilution in `H_(2)O` at `25^(@)C`.

A

517.2

B

552.7

C

390.7

D

217.5

Text Solution

Verified by Experts

The correct Answer is:
C
`Lambda_(HOAc)^(oo)=Lambda_("HCl")^(oo)-Lambda_(NaCl)^(oo)`
`=91.0+426/2-126.5"S.cm"^(2)."mol"^(-1)`
`=390.7"S.cm"^(2)."mol"^(-1)`
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