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0.1 M solution is present in a conductiv...

0.1 M solution is present in a conductivity cell wich electrode of `100cm^(2)` area placed 1 cm apart and resistance observed is `5xx10^(3)` ohm. What is the molar conductivity of this solution?

A

`5xx10^(2)"S.cm"^(2)."mol"^(-1)`

B

`10^(4)"S.cm"^(2)."mol"^(-1)`

C

`200"S.cm"^(2)."mol"^(-1)`

D

`0.02"S.cm"^(2)."mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
Molar conductivity, `Lambda_(m)=(kappaxx1000)/(M)`
M = molarity and `kappa` = specific conductivity
`kappa xx(1)/(R)xx"cell constant"`
`=(1)/(R)xx(l)/(R)=(1)/(5xx10^(3)Omega)xx(1cm)/(100cm^(2))`
`=2xx10^(-6)Omega^(-1).cm^(-1)`
`therefore" "Lambda_(m)=(2xx10^(-6)xx1000)/(0.1)="0.02S.cm"^(2)."mol"^(-1)`
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