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Time taken to completely decompose 36 g ...

Time taken to completely decompose 36 g of water by passing 3A current is -

A

35.8 h

B

40 h

C

51.8 h

D

22.5 h

Text Solution

Verified by Experts

The correct Answer is:
A
`underset("36 g")(2G_(2)O)rarr 2H_(2)+O_(2)`
2 mol of `H_(2)O-="4 mol of e"`
4 F of charge is required for complete decomposition.
Now, `Q=Ixxt`
`therefore" "t=(Q)/(I)=(4xx96500)/(3)=128666s`
`=(128666)/(3600)=35.8h`
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