The conversion of molecules X to Y follows second order kinetics . If concentration of X is increased to three times how will it affect the rate of formation of Y ?

Explanation

The reaction is `XrarrY`
Reaction -rate `-(d[X])/(dt)=(d[Y])/(dt)=k[X]^(2)`
Therefore , rate of formation of `Y,(d[Y])/(dt)=k[X]^(2)`
i.e., `(d[Y])/(dt)prop[X]^(2)`
Hence , if concentration of X is increased to three times , the rate of formation of Y will increase by 9 times.