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When K(2)Cr(2)O(7) is treated with H(2)O...

When `K_(2)Cr_(2)O_(7)` is treated with `H_(2)O_(2)` in acidic medium, in presence and in absence of org. solvent. The oxidation state of chromium finally:

A

increases and decreases respectively

B

decreases and increases respectively

C

retained same and decreases respectively

D

retained same in both cases

Text Solution

Verified by Experts

The correct Answer is:
C
`Cr_(2)O_(7)^(2-)+H_(2)O_(2) rarr CrO_(5)+H_(2)O`
`4CrO_(5) +12H^(+) rarr 4Cr^(3+) +7O_(2) uarr +6H_(2)O`
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