An organic compound [A], whose molecular formula is `C_(3)H_(6)O`, gives iodoform reaction and forms compound [B]. Compound [B], when heated with silver powder, converts into compound [C}. Compound [C] reacts with dil. Sulphuric acid and mercuric sulphate to obtain compound [D], which gives Aldol condensation reaction. Write down the names of all compounds from [A] to [D] and also write the chemical equations for each step.

Explanation

To solve the problem step by step, we will identify each compound from [A] to [D], write their names, and provide the corresponding chemical equations.

### Step 1: Identify Compound [A]
Given the molecular formula \( C_3H_6O \) and the fact that it gives an iodoform reaction, we can conclude that compound [A] is a methyl ketone. The only possible structure that fits this description is propanone.

**Compound [A]: Propanone (Acetone)**
- Structure: \( CH_3COCH_3 \)

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