If the concentration of glucose `(C_(6)H_(12)O_(6))` in blood is 0.9 g `L^(-1)`. What will be the molarity of glucose in blood?

Options

A. 5M
B. 50M
C. 0.005M
D. 0.5M

Answer

C

Explanation

In the given question 0.9 `gL^(-1)` means that 1000(mL) solution contains 0.9g of glucose.
`therefore` Number of moles `=0.9g "glucose"=(0.9)/(180)` mol glucose
`=5xx10^(-3)` mol glucose
(where , molecular mass of glucose `(C_(6)H_(12)O_(6))=12xx6+12xx1+6xx16=180u`)
i.e. L solution contains 0.05 mole glucose or the molarity of glucose is 0.005M.