The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction `2A+4Brarr3C+4D`, when 5 moles of A react with 6 moles of B, then
(a) which is the limiting reagent?
(b) calculate the amount of C formed?

Explanation

`2A+4Brarr3C+4D`
According to the given reaction, 2 moles of A react with 4 moles of B
Hence 5 moles of A will react with 10 moles of `B((5xx4)/(2)=10"moles")`
(a) It indicates that reactant B is limiting reagent as it will consume first in the reaction becuase we have only 6 moles of B.
(b) Limiting reagent decide the amount of product produced
According to the reaction.
4 moles of B produces 3 moles of C
`therefore` 6 moles of B will produce `(3xx6)/(4)=24` moles of C