Match the following.

Explanation

A. Number of moles of `CO_(2)` molecule `=("Weight in gram of" CO_(2))/("molecular weight of " CO_(2))=(88)/(44)=2` mol
B. 1 mole of a substance `=N_(A)` molecules `=6.022xx10^(23)` molecuels
=Avogadro number
`=6.022xx10^(23)` molecuels of `H_(2)O=1` mol
C. 22.4L of `O_(2)` at StP=1 mol
D. Number of moles of 96g of `O_(2)=(96)/(32)"mol"=3"mol"`
E. 1 mole of any gas=Avogadro number `=6.022xx10^(23)` molecuels