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For reaction, PCl(3)(g)+Cl(2)(g) hArr ...

For reaction,
`PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g)`
the value of `K_(c)` at `250^(@)C` is 26. The value of `K_(p)` at this temperature will be .

A

0.6055

B

0.57

C

0.83

D

0.46

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(p)=K_(c) (RT)^(Deltan)=26(82.05xx523)^(-1)`
`=(26)/(82.05xx523)=6.06xx10^(-4)`
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