1 mol of `N_(2)` and 2 mol of `H_(2)` are allowed to react in a 1 `dm^(3)` vessel. At equilibrium, `0.8` mol of `NH_(3)` is formed. The concentration of `H_(2)` in the vessel is

Options

A. 0.6 mole
B. 0.8 mole
C. 0.2 mole
D. 0.4 mole

Answer

B

Explanation

`{:(,N_(2),+,3H_(2),hArr , 2NH_(3)),("Initial ",1 "mol",,2"mol",,),("At eq.",1-0.4=0.6"mol",,2-3xx0.4=0.8"mol",,0.8"mol"):}`
Formation of 0.8 mol of `NH_(3)` means of 0.4 mol `N_(2)` have reacted