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The rate of forward reaction is two time...

The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration. `K_(equilibrium)` is

A

0.5

B

1.5

C

2.5

D

2

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(eq)=K_(f)//K_(b)=2//1=2`
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DINESH PUBLICATION-PHYSICAL AND CHEMICAL EQUILIBRIA-REVISION QUESTION FROM COMPETITIVE EXAMS
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