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The equilibrium constant for the followi...

The equilibrium constant for the following reaction will be
`3A+2B rarr C`

A

`([3A][2B])/([C])`

B

`([C])/([3A][2B])`

C

`([C])/([A]^(2)[B]^(2))`

D

`([C])/([A]^(3)[B]^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
`K_(c)=("Product of active masses of the products")/("Product of active masses of the reactants")`
`=(C )/([A]^(3)xx[B]^(2))`
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