A schematic plot of In `K_(eq)` versus inverse o ftemperature for a reaction is shown below

the reaction must be:

Options

A. exothermic
B. Endothermic
C. one with negligible enthalpy change
D. highly spontaneous at ordinary temperature

Answer

A

Explanation

Integrated form of van't Hoff equation
`ln K_(p)=-(DeltaH^(@))/(R )(1)/(T)+I`
The given line has a+ve slpe
`:. -(DeltaH^(@))/(R)gt0` ltbgt `implies DeltaH^(@) lt 0 ( :. R =0.0821 L ` atm `K^(-1)mol^(-1))`
Thus , the reaction is exothermic in nature.