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For the reaction H(2)(g)+CO(g)hArrCO(g)...

For the reaction
`H_(2)(g)+CO(g)hArrCO(g)+H_(2)O(g),` if the initial concentration of`[H_(2)]=[CO_(2)]`and x moles /litres of hydrogen is consummed at equilibrium , the correct expression of `K_(p)` is :

A

`(x^(2))/((1-x)^(2))`

B

`((1+x)^(2))/((1-x))`

C

`(x^(2))/(2+x^(2))`

D

`x^(2)/(1-x^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A

`{:(,H_(2)(g),+,CO_(2)(g),hArr,CO(g),+,H_(2)O(g)),("Initial conc.",1,,1,,0,,0),("At eqm.",1-x,,1-x,,x,,x):}`
`K_(c)=(x xx x)/((1-x)(1-x))=(x^(2))/((1-x)^(2))`
`K_(p)=K_(c) ( :' Deltan_(g)=0)`
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