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100 mL of phosphine (PH(3)) on hearing f...

`100 mL` of phosphine `(PH_(3))` on hearing forms phosphorous `(P)` and hydrogen `(H_(2))`. The volume change in the reaction is

A

an increase of 50 mL

B

an increase of 100 mL

C

an increase of 150 Ml

D

a decrease of 50 Ml

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(4PH_(3)(g) ,hArr,4P(s),+,6H_(2)(g)),(4 "vol",,,,6 "vol"),(100mL,,,,(100xx6)/(4)=150mL):}`
Change in volume `=(150-100)mL =50 mL`
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