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For the reaction C(s) +CO(2)(g) rarr 2CO...

For the reaction `C(s) +CO_(2)(g) rarr 2CO(g), k_(p)=63` atm at 100 K. If at equilibrium `p_(CO)=10p_(CO_(2)) ` then the total pressure of the gases at equilibrium is

A

6.3 atm

B

6.93 atm

C

0.63 atm

D

0.693 atm

Text Solution

Verified by Experts

The correct Answer is:
B
`C(s) +CO_(2)(g) hArr 2CO(g)`
`k_(p)=(p_(CO^(2)))/(p_(CO))` or 63=((10p_(CO_(2)))^(2))/(p_(CO_(2)))`
`p_(CO_(2))=(63)/(100)=0.63 atm`
`p_(CO)=10p_(CO_(2))=10xx0.63atm =6.3`
`:. p_("total")=p_(CO_(2))+p_(CO)=0.63+6.3`
`=6.93`
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