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'Stability of carbocations depends upon ...

'Stability of carbocations depends upon the electron releasing inductive effect of groups adjacent to positively charged atom involvement of neighbouring groups in hyperconjugation and resonace''.
The structure of triphenylmethyl cation is given below. This is very stable and some of its salts can be stored for months. Explain the cause of high stability of this cation

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In triphenylmethyl cation, due to resonance, the positive charge can move at both the `o-`and `p-` position of each benzene ring. This is illustrated below.

Since, there are three benzene rings, hence, there are, in all resonance structure. Thus, triphenylmethyl cation is highly stable due to these nine resonance structure.
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"Stability of carbocations depends upon the electron releasing inductive effect of groups adjacent to positively charged carbon atom involvement of neighbouring groups in hyperconjugation and resonance." The structure of triphenylmethyl cation is given below. This is very stable and some of its salts can be stored for months. Explain the cause of high stability of this cation.

"Stability of carbocations depends upon the electron releasing inductive effect of groups adjacent to positively charged carbon atom involvement of neighbouring groups in hyperconjugation and resonance." Which of the following ions is more stable ? Use reasonance to explain your answer.

'Stability of carbocations depends upon the electron releasing inductive effect of groups adjacent to positively charged atom involvement of neighbouring groups in hyperconjugation and resonace''. Write structure of various carbocations that can be obtained from 2-methylbutane. Arrange these carbocations in order of increasing stability

'Stability of carbocations depends upon the electron releasing inductive effect of groups adjacent to positively charged atom involvement of neighbouring groups in hyperconjugation and resonace''. Draw the possible resonance structures for CH_(3) - underset(..)overset(..)(O) - overset(+)(C) H_(2) and predict which of the structures is more stable. Give reason for your answer.

Hyperconjugation describes the orbital interactions between the pi -system and the adjacent sigma -bond of the substituent group(s) in organic compounds. Hyperconjugation is called as Baker and Nathan effect. The necessary and sufficient conditions for the hyperconjugation are: (i) Compound should have at least one sp^(2) -hybrid carbon of either alkene, carbocation or alkyl free radical. (ii) alpha -carbon with respect to sp^(2) -hybrid carbon should have at least one hydrogen. Hyperconjugation are of three types: (i) sigma(C-H),pi -conjugation, (ii) sigma(C-H), positive charge conjugation, (iii) sigma(C-H) , odd electron conjugation. The hyperconjugation may be represented as, Number of resonating structures due to hyperconjugation =(n+1) , where n is the numebr of alpha -hydrogen. Greater is the number of such forms, more is the stability of the species under consideration. Stability of alkyl carbocations can be explained by

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