Show that if two chords of a circle bisect one another they must be diameters.

Explanation

Given-> 2 chords AB and CD

O is midpoint of AB and CD

To prove->AB and CD are diameter

Proof->`/_AOC and /_BOD`

`/_AOC=/_BOD`

`OA=OB`

`OC=OD`

`/_AOC cong /_BOD(SAS)`

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