The rate constant of a reaction increases by 7% when its temperature is raised from 300 K to 310 K, while its equilibrium constant increases by 3%. Calculate the activation energy of the forward and reverse reactions.

Explanation

To solve the problem of calculating the activation energy of the forward and reverse reactions based on the given temperature change and the percentage increase in rate and equilibrium constants, we can follow these steps:

### Step 1: Understand the Given Data
We are given:
- Initial temperature, \( T_1 = 300 \, K \)
- Final temperature, \( T_2 = 310 \, K \)
- Increase in rate constant, \( K_2 = 1.07 K_1 \) (7% increase)
- Increase in equilibrium constant, \( K_{eq,2} = 1.03 K_{eq,1} \) (3% increase)
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