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At 380^(@)C , the half-life periof for t...

At `380^(@)C` , the half-life periof for the first order decompoistion of `H_(2)O_(2)` is `360 min`. The energy of activation of the reaction is `200 kJ mol^(-1)`. Calculate the time required for `75%` decompoistion at `450^(@)C`.

Text Solution

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`K_(1) =0.693//360" min"^(-1)" at "653 K and " "E_(a) =200xx10^(3)J`,
`K_(2)=?" at "723 K," "R=8.314 J`
`therefore" From "2.303 log_(10)(K_(2)//K_(1))=(E_(a)//R) [(T_(2)-T_(1))(T_(1) T_(2))]`
`K_(2) =0.068" min"^(-1)`
Now, `" "t=(2.303)/(0.068) log_(10) ""(100)/(25) =20.39` minute
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