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The reaction A(g)+2B(g)rarrC(g)+D(g) is ...

The reaction `A(g)+2B(g)rarrC(g)+D(g)` is an elementary process. In an experiment, the initial partial pressure of `A` and `B` are `P_(A)= 0.60` and `P_(B)= 0.80 atm`. When `P_(C )=0.2 atm`, the rate of reaction relative to the initial rate is

A

`1//48`

B

`1//24`

C

`9//16`

D

`1//6`

Text Solution

Verified by Experts

The correct Answer is:
D
`A(g) +2B(g) rarr C(g) +D(g)`
`t=0" "0.60" "0.80" "0" "0`
`t=t" "(0.6-0.2)(0.8-2xx0.2)0.2" "0.2`
`("Rate")_(i) =k [A][B]^(2)=k[0.6] [0.8]^(2)`
`("Rate")_(t)=[0.4][0.4]^(2)`
`(R_(t))/(R_(i))=(k[0.4]^(3))/(k[0.6][0.8]^(2))=(1)/(6)`
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