Ethylidene chloride (`CH_(3)CHCl_(2)`) on hydrolysis with NaOH gives -

Options

A. `CH_(3)`CHO
B. `CH_(3)COCH_(3)`
C. `CH_(3)CH(OH)_(2)`
D. `C_(2)H_(5)`OH

Answer

To solve the problem of what product is formed when Ethylidene chloride (`CH3CHCl2`) undergoes hydrolysis with NaOH, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of Ethylidene Chloride**:
Ethylidene chloride is a geminal dihalide, which means it has two halogen atoms attached to the same carbon atom. The structure can be represented as:
\[ CH_3 - C(Cl)_2 \]
where one carbon is bonded to two chlorine atoms.

2. **Reaction with NaOH**:
When Ethylidene chloride is treated with sodium hydroxide (NaOH), hydrolysis occurs. The hydroxide ion (OH⁻) from NaOH acts as a nucleophile and attacks the carbon atom bonded to the chlorine atoms.

3. **Nucleophilic Substitution**:
The nucleophilic substitution reaction will replace the chlorine atoms with hydroxyl groups (OH). The reaction can be represented as:
\[ CH_3 - C(Cl)_2 + 2 NaOH \rightarrow CH_3 - C(OH)_2 + 2 NaCl \]
Here, two hydroxyl groups replace the two chlorine atoms.

4. **Formation of Aldehyde**:
The product formed, `CH3C(OH)2`, has two hydroxyl groups on the same carbon, which is unstable. To stabilize the compound, a water molecule (H₂O) is eliminated. This results in the formation of a double bond between carbon and oxygen:
\[ CH_3 - C(OH)_2 \rightarrow CH_3 - C=O + H_2O \]
The resulting compound is acetaldehyde, which can be represented as:
\[ CH_3CHO \]

5. **Final Product**:
The final product of the hydrolysis of Ethylidene chloride with NaOH is acetaldehyde (ethanal).

### Final Answer:
The product obtained from the hydrolysis of Ethylidene chloride (`CH3CHCl2`) with NaOH is **acetaldehyde (ethanal)**.