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The vapour pressure of pure liquid solve...

The vapour pressure of pure liquid solvent `A` is `0.80 atm`. When a non-volatile substance `B` is added to the solvent, its vapour pressure drops to `0.60 atm`, the mole fraction of component `B` in the solution is

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The vapour pressure of pure liquid solvent A is 0.80 atm.When a non volatile substances B is added to the solvent, its vapour pressure drops to 0.60 atm. Mole fraction of the components B in the solution is:

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The vapour pressure of a solvent decreased by 10 mm of Hg when a non-volatile solute was added to the solvent. The mole fraction of solute is 0.2 , what would be the mole fraction of solvent if the decrease in vapour pressure is 20 mm of Hg .

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MOTION-LIQUID SOLUTION-EXERCISE-3 SUBJECTIVE JEE ADVANCED
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