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n mole of PCl(3) and n mole of Cl(2) are...

`n` mole of `PCl_(3)` and `n` mole of `Cl_(2)` are allowed to react at constant temperature `T` to have a total equilibrium pressure `P` , as `:`
`PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g)`
If `y` mole of `PCl_(5)` are formed at equilibrium , find `K_(p)` for the given reaction .

Text Solution

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`((2n-y)y)/((n-y)^2P)`
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