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The equilibrium pressure of NH(4)CN(s)...

The equilibrium pressure of
`NH_(4)CN(s) hArr NH_(3)(g)+HCN(g)` is `2.98` atm. Calculate `K_(p)`. If `NH_(4)CN(s)` is allowed to decompose in presence of `NH_(3)` at `0.25` atm, calculate partial pressure of `HCN` at equilibrium.

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`0.22 "atm"^2 , 0.069 atm`
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