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When 20 g of CaCO(3) were put into 10 li...

When `20 g` of `CaCO_(3)` were put into `10 litre` flask and heated to `800^(@)C`, `35%` of `CaCO_(3)` remained unreacted at equilibrium. `K_(p)` for decomposition of `CaCO_(3)` is :

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1.145atm
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When 20 g of CaCO_3 were put into 10 litre flask and heated to 800^@C, 30% of CaCO_3 remained unreacted at equilibrium K_p for decomposition of CaCO_3 will be

When 20g of CaCO_3 is put into a 11.45L flask and heated to 800^@C , 35% of CaCO_3 remains undissociated at equilibrium. Calculate the value of K_p .

Write the equilibrium constant for the dissociation of CaCO_(3) .

10 g of CaCO_(3) contains

10 g of CaCO_(3) contains :

For the reaction CaCO_(3)(s) hArr CaO(s) was put in to 10 L container and heated to 800^(@)C , what percentage of the CaCO_(3) would remain unreacted at equilibrium.

For the reaction CaCO_(3)(s) hArr CaO(s) + CO_(2)(g) K_(p)=1.16 atm at 800^(@)C . If 20.0g of CaCO_(3) was put into a 10.0 L flask and heated to 800^(@)C, what percentage of CaCO_(3) would remain unreacted at equilibrium ?

For the reaction CaCO_(3) (s) hArr CaO (s) + CO_(2) (g), K_(p) = 1*16 " atm . If "20* 0" g of " CaCO_(3) " is heated to " 800^(@)C" in a 10 litre container, what % of "CaCO_(3) " would remain unreached at equilibrium ? ( Mol. wt. of " CaCO_(3) = 100, R = 0*0821 " L atm mol"^(-1) K^(-1) )

20gm of CaCO_(3) on decomposition gives CO_(2) at STP:

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