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For the equilibrium: LiCl.3NH(3(s))hAr...

For the equilibrium:
`LiCl.3NH_(3(s))hArrLiCl.NH_(3(s))+2NH_(3)`, `K_(p)=9 atm^(2)`
at `40^(@)C`. A `5 litre` vessel contains `0.1` mole of `LiCl.NH_(3)`. How many mole of `NH_(3)` should be added to the flask at this temperture to derive the backward reaction for completion?

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0.7837 mole
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