Mole fraction of `I_2` in `C_6H_6` is 0.2. Calculate molality of I2 in `C_6H_6`.

Explanation

To calculate the molality of \( I_2 \) in \( C_6H_6 \) (benzene) given that the mole fraction of \( I_2 \) is 0.2, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Definitions**:
- **Mole Fraction** (\( X \)): The mole fraction of a component in a solution is defined as the number of moles of that component divided by the total number of moles of all components in the solution.
- **Molality** (\( m \)): Molality is defined as the number of moles of solute per kilogram of solvent.

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