A and B are enantiomer to each other . If specific rotation of A is + `20^(@)` rotaion of mix of A and B is `-10^(@)` then find the percentage of A and B in the mixture ?

Explanation

To solve the problem of determining the percentage of enantiomers A and B in the mixture, we can follow these steps:

### Step 1: Understand the properties of enantiomers
Enantiomers are compounds that are mirror images of each other and have opposite optical rotations. Given that the specific rotation of A is +20°, the specific rotation of B will be -20°.

### Step 2: Set up the equation for the mixture
Let’s assume we have x moles of A and (1 - x) moles of B in the mixture. The total optical rotation of the mixture is given as -10°.

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