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Molecular formulae of an optically activ...

Molecular formulae of an optically active organic compound is
`C_(4) H_(10) O` . Its structure is

A

`C_(2) H_(5) OC_(2) H_(5)`

B

`CH_(3) OC_(3) H_(7)`

C

`CH_(3) CH_(2) CH_(2) CH_(2) OH`

D

`CH_(3) CHOHCH_(2) CH_(3)`

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The correct Answer is:
To determine the structure of an optically active organic compound with the molecular formula C4H10O, we need to identify a structure that contains a chiral center. A chiral center is typically a carbon atom bonded to four different groups. ### Step-by-Step Solution: 1. **Identify the Molecular Formula**: The given molecular formula is C4H10O. This indicates that the compound contains 4 carbon atoms, 10 hydrogen atoms, and 1 oxygen atom. 2. **Understand Optical Activity**: A compound is optically active if it has at least one chiral center. A chiral center is a carbon atom that is bonded to four different substituents. 3. **Explore Possible Structures**: We need to explore different structural isomers of C4H10O to find one with a chiral center. The common structural forms for this molecular formula include: - Butanol (1-butanol, 2-butanol, etc.) - Ether structures (like diethyl ether) - Other possible arrangements. 4. **Examine Each Structure for Chirality**: - **1-Butanol**: CH3-CH2-CH2-CH2OH (not chiral) - **2-Butanol**: CH3-CH(OH)-CH2-CH3 (this has a chiral center) - **Diethyl ether**: CH3-CH2-O-CH2-CH3 (not chiral) - **Isobutyl alcohol**: CH3-CH(CH3)-CH2OH (not chiral) - **Butyl methyl ether**: CH3-CH2-CH2-O-CH3 (not chiral) 5. **Identify the Chiral Center**: In the case of 2-butanol (CH3-CH(OH)-CH2-CH3), the carbon atom bonded to the hydroxyl group (OH) is attached to four different groups: - Methyl group (CH3) - Hydroxyl group (OH) - Ethyl group (CH2-CH3) - Hydrogen atom (H) 6. **Conclusion**: Since 2-butanol has a chiral center, it is optically active. Therefore, the structure of the optically active organic compound with the molecular formula C4H10O is 2-butanol. ### Final Structure: The structure of the optically active compound is: ``` CH3 | CH3-CH-CH2-CH3 | OH ```
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MOTION-ISOMERISM-Exercise 1
  1. (2R,3r)-2,3 bantanediol is :

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  2. Which of the following heptanols are chiral: 1-heptanol, 2-heptanol, 3...

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  3. Molecular formulae of an optically active organic compound is C(4)...

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  4. The process of separation of racemic modifications into d and l enanti...

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  5. Which of the following compounds may not exist as enantiomers?

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  6. Meso form of tartaric acid is –

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  7. How many asymmetric carbon atoms are present in - (i) 1,2-dimethyl c...

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  8. The number of geometrical isomers of CH(3)CH=CH-CH=CH-CH=CHCl is -

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  9. The number of optically active isomer possible for CH(3)-underset(OH)u...

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  10. A compound can be divided into two equal halves & contains even 'n' as...

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  11. Number of optically active isomers of tartaric acid is – underset(C...

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  12. Isomers which can be interconverted through rotation around a single b...

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  13. CH(3)-CH(2)-CH(2)-CH(3). There is free rotation about (C(2)ul(sigma)C(...

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  14. The total number of conformations of ethane is:

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  15. The eclipsed and staggered conformation of ethane is due to -

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  16. What are the type of isomers in following pairs-

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  17. At room temperature the eclipsed and the staggered forms of ethane can...

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  18. The phenomenon involving the migration of a proton to give two structu...

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  19. Which of the following compounds can exhibit tautomerism

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  20. Tautomerism is exhibited by -

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