On chlorination of propane number of products of the formula `C_(3)H_(6) C1_(2)` is

Options

A. 3
B. 4
C. 5
D. 6

Answer

To determine the number of products formed from the chlorination of propane with the formula C₃H₆Cl₂, we will follow these steps:

### Step 1: Understand the Structure of Propane
Propane (C₃H₈) has the following structure:
- CH₃-CH₂-CH₃
- In propane, there are three carbon atoms: two primary (CH₃) and one secondary (CH₂).

### Step 2: Identify Possible Chlorination Sites
When chlorination occurs, chlorine (Cl) can replace hydrogen (H) atoms at different positions:
- Chlorination can occur at the primary carbon atoms (CH₃) or the secondary carbon atom (CH₂).

### Step 3: Determine the Possible Products
1. **Chlorination at both primary carbons:**
- CH₂Cl-CH₂-CH₃ (1st product)

2. **Chlorination at one primary and one secondary carbon:**
- CH₃-CHCl-CH₂Cl (2nd product)

3. **Chlorination at both secondary carbons:**
- CH₃-CHCl-CH₂ (3rd product)

4. **Chlorination at one primary and one secondary carbon (different arrangement):**
- CH₂Cl-CHCl-CH₃ (4th product)

### Step 4: Check for Chiral Centers
- A chiral center is a carbon atom that has four different substituents.
- In the product CH₃-CHCl-CH₂Cl, the carbon with Cl, CH₃, H, and CH₂Cl is a chiral center, leading to optical isomers.

### Step 5: Count the Total Products
- We have identified 4 structural isomers.
- Among these, one of the products is chiral, which means it can exist in two optical forms (enantiomers).

### Conclusion
Thus, the total number of products formed from the chlorination of propane with the formula C₃H₆Cl₂ is:
- 4 structural isomers + 1 pair of enantiomers = 5 total products.

### Final Answer
The total number of products is **5**.

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