`Ph-overset(O)overset(||)(C)-CH_(3)overset(PCI_(5))rarr` Product is

Options

A. `Ph-underset(CI)underset(|)overset(CI)overset(|)(C)-CH_(3)`
B. `Ph-underset(CI)underset(|)(CH)-underset(CI)underset(|)(CH_(2))`
C.
D. `Ph — CH_(2) — CH_(2) — Cl`

Answer

To solve the question regarding the reaction of the compound with phosphorus pentachloride (PCl5), we need to analyze the structure and the reaction step-by-step.

### Step 1: Identify the Reactants
The reactant given is a compound with the structure:
- pH (phenyl group)
- C=O (carbonyl group)
- CH3 (methyl group)

This can be represented as:
- Ph-C(=O)-CH3

### Step 2: Understand the Role of PCl5
PCl5 is a chlorinating agent that can convert alcohols and carbonyl compounds into chlorides. In this case, it will react with the carbonyl oxygen.

### Step 3: Reaction Mechanism
1. The lone pair of electrons on the oxygen atom of the carbonyl group will attack one of the chlorine atoms in PCl5, leading to the formation of a chlorinated intermediate.
2. This results in the formation of a positively charged oxonium ion (Ph-C(=O)Cl-CH3) and the release of Cl-.

### Step 4: Chloride Ion Attack
3. The Cl- ion that was released can now attack the carbon atom of the carbonyl group, leading to the substitution of the carbonyl oxygen with a chlorine atom.
4. This results in the formation of a new product.

### Step 5: Final Product
5. The final product of this reaction will be a compound where the carbonyl oxygen is replaced by a chlorine atom, leading to the formation of:
- Ph-C(Cl)-CH3 (with the remaining chlorine atoms from PCl5).

### Conclusion
The final product of the reaction of Ph-C(=O)-CH3 with PCl5 is:
- Ph-C(Cl)-CH3 and POCl3 (as a by-product).

### Summary of the Product
The product formed is:
- **Ph-CHCl-CH3** (with POCl3 as a by-product).

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