`Ph-underset(Br)underset(|)(CH)-overset(Br)overset(|)(CH_(2))underset(("x=No.of moles of NaNH"_(2)))overset((x)NaNM_(2))rarrPh-C=""^(Ө)CNoverset(oplus)(a)` Value of x is

Options

A. 1
B. 2
C. 3
D. 4

Answer

To solve the question regarding the value of \( x \) (the number of moles of NaNH2 used), we need to analyze the reaction involving the alkyl halide and NaNH2.

### Step-by-Step Solution:

1. **Identify the Structure**:
The compound given is a phenyl bromide derivative with two bromine substituents and two carbon chains. The structure can be represented as:
\[ \text{Ph-}Br-\text{C}(\text{Br})-\text{CH}_2 \]

2. **Understanding the Role of NaNH2**:
Sodium amide (NaNH2) is a strong base. It is used to deprotonate acidic protons from the alkyl halide. In this case, it will abstract protons from the carbon chains, leading to the formation of a carbon anion.

3. **Determine the Number of Acidic Protons**:
In the given structure, we need to identify how many acidic protons are available for abstraction. Typically, the protons on the carbon adjacent to the halogen (in this case, bromine) are acidic due to the electronegative halogen's influence.

4. **Calculate the Moles of NaNH2 Required**:
- Each acidic proton will require one mole of NaNH2 to be abstracted.
- In the structure, there are two bromine substituents, and each carbon chain has one acidic proton available for abstraction.
- Therefore, the total number of moles of NaNH2 required is equal to the number of acidic protons, which is 2.

5. **Final Answer**:
Thus, the value of \( x \) (the number of moles of NaNH2) is:
\[ x = 2 \]