Home
Class 12
MATHS
The graph of the function y = g(x) is sh...

The graph of the function y = g(x) is shown. The number of solutions of the equationm `abs(absg(x)-1)=1/2`, is

A

4

B

5

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • FUNCTION

    MOTION|Exercise Exercise - 2 (Level-I)|33 Videos
  • FUNCTION

    MOTION|Exercise Exercise - 2 (Level-II)|6 Videos
  • FUNCTION

    MOTION|Exercise Exercise - 4 | Level-II|7 Videos
  • ELLIPSE

    MOTION|Exercise Exercise - 4 | Level-I Previous Year | JEE Main|20 Videos
  • HYPERBOLA

    MOTION|Exercise EXERCISE-4 (Level-II)|17 Videos

Similar Questions

Explore conceptually related problems

The graph of the function y=g(x) is shown.The number of solutions of the equation |g(x)|-1|=(1)/(2), is

The graph of the function y=f(x) is shown. Find the number of solutions to the equation ||f(x)|-1|=(1)/(2) .

The graph of y = f(x} is shown, then the number of solutions of f(f(x}} = 2 will be

Find number of real solutions of the equation x(x^2+abs(x)+5abs(x-1)-6abs(x-2)=0

The graph of the function y=f(x) is shown in the adjacent figure then correct statement is

Draw the graph of the function f(x) = (1+1/x)^(2)

If the graph of the function y = f(x) is as shown : The graph of y = 1//2(|f(x)|-f(x)) is

The absolute valued function f is defined as f(x) = {{:(x,, x ge 0),(-x ,, x lt 0):}} and fractional part function g(x) as g(x) = x-[x], graphically the number of real solution(s) of the equation f(x) = g(x) is obtained by finding the point(s) of interaction of the graph of y = f(x) and y = g(x). The number of solutions (s) of |x-1| = {x}, x in [-1, 1] is

The absolute valued function f is defined as f(x) = {{:(x,, x ge 0),(-x ,, x lt 0):}} and fractional part function g(x) as g(x) = x-[x], graphically the number of real solution(s) of the equation f(x) = g(x) is obtained by finding the point(s) of interaction of the graph of y = f(x) and y = g(x). The number of solution (s) |x-1| - |x+2| = k , when -3 lt k lt 3

MOTION-FUNCTION-Exercise - 1 ( JEE Main)
  1. Let f(x)=abs(x-1)+abs(x-2)+abs(x-3)+abs(x-4), then

    Text Solution

    |

  2. Fundamental period of f(x)=sec(sin x) is

    Text Solution

    |

  3. The period of sin(pi/4)x+cos(pi/2)x+cos(pi/3)x is

    Text Solution

    |

  4. Let f(x)=x(2-x), 0<=x<=2. If the definition of f is extended over the ...

    Text Solution

    |

  5. The peroid of the function f(x) =(|sinx|-|cosx|)/(|sin x + cosx|) i...

    Text Solution

    |

  6. Which of the following is implicit functions -

    Text Solution

    |

  7. I fy=f(x) satisfies the condition f(x+1/x)=x^2+1/(x^2)(x!=0) then f(x...

    Text Solution

    |

  8. If f(x) = a(x^n +3), f(1) = 12, f(3) = 36, then f(2) is equal to

    Text Solution

    |

  9. Let f:(2,4)->(1,3) be a function defined by f(x)=x-[x/2], thenf^(-1)(x...

    Text Solution

    |

  10. Let f(x) = (x+1)^(2) - 1, (x ge - 1). Then, the set S = {x : f(x) = f^...

    Text Solution

    |

  11. A function f : R->R satisfies the condition x^2f(x)+f(1-x)=2x-x^4. The...

    Text Solution

    |

  12. Let f(x) = abs(x – 1). Then :

    Text Solution

    |

  13. Let g(x) = 1 + x – [x] and f(x)={:{(-1,if,xlt0),(0,if, x=0),(1,if,x gt...

    Text Solution

    |

  14. Let f: [0, 1] to [1, 2] defined as f(x) = 1 + x and g : [1, 2] to [0, ...

    Text Solution

    |

  15. Let f(x)={{:(1+x",", 0 le x le 2),(3-x"," ,2 lt x le 3):} find (fof)...

    Text Solution

    |

  16. f(x) = |x-1|, f: R^+->R, g(x) = e^x, g:[-1,oo)->R. If the function fog...

    Text Solution

    |

  17. Number of solution of 6 abscosx = x " in"[ 0.2pi] is

    Text Solution

    |

  18. The graph of the function y = g(x) is shown. The number of solutions o...

    Text Solution

    |

  19. If f(x) = sin^44x - cos^44 &g(x) = sin x + cosx. Then general solution...

    Text Solution

    |

  20. Which of the following is not Bounded function

    Text Solution

    |