Home
Class 12
PHYSICS
A unifrom rope of mass 0.1kg and length ...

A unifrom rope of mass 0.1kg and length 2.45 m hangs from a rigid support. The time taken by the transverse wave formed in the rope to travel through the full length of the rope is (Assume g=`=9.8 m//s^2`)

A

0.5 s

B

1.6 s

C

1.2 s

D

1.0 s

Text Solution

Verified by Experts

The correct Answer is:
D

The time taken by the tranverse wave to travel full length rope is,
`t=2sqrt(l/g)=2sqrt(2.45/9.8)=1 s`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMAL CONDUCTIVITY

    SIA PUBLICATION|Exercise Problems|96 Videos
  • WAVES OPTICS

    SIA PUBLICATION|Exercise M.C.Q|23 Videos

Similar Questions

Explore conceptually related problems

A reniform rope of mass 0.7 kg and length 2.45 in hangs from a ceiling (a) Find the speed of Transverse wave in the rope at a point 0.5m distrus from the lower end, b) Puste Calculate the time taken by a transverse wave to travel the full length of the rope (g=9.8m//s^(2)) .

A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support. A block of mass 2 kg is attached to the free end of the rope. A transverse pulse of wavelength 0.06 m is produced at the lower end of the rope. What is the wavelength of the pulse when it reaches the top of the rope ?

Knowledge Check

  • A uniform rope having mass m hangs vertically from a rigid support. A transverse wave pule is produced at the lower end. The speed v of wave pulse varies with height h from the lower end as:

    A
    B
    C
    D
  • A uniform rope of length L and mass m_(1) hangsvertically from a rigid support. A block of mass m_(2) is attached to the free end of the rope. A transverse pulse of wavelength lambda_(1) is produced at the lower end of the rope. The wavelength of the pules when it reaches the top of the rope is lambda_(2) . The ratio lambda_(2)//lambda_(1) is :

    A
    `sqrt((m_(1))/(m_(2))`
    B
    `sqrt((m_(1)+m_(2))/(m_(2)))`
    C
    `sqrt((m_(2))/(m_(2)))`
    D
    `sqrt((m_(1)+m_(2))/(m_(1)))`
  • A uniform rope having some mass hangs vertically from a rigid support. A transverse wave pulse is produced at the lower end. The speed (v) Of the wave pulse varies with height (h) from the lower end as:

    A
    B
    C
    D
  • Similar Questions

    Explore conceptually related problems

    A heavy but uniform rope of length L is suspended from a ceiling, Write the velocity of a transverse wave travelling on the string as a funtion of the distance from the lower end.

    A wave pulse starts propagating in the x direction along a non uniform wire of length 10m with mass per unit length is given by mu = mu_(0) + ax and under a tension of 100N. The time taken by a pulse to travel from the lighter end to heavier end (mu_(0) = 10^(-2) kg//m " and " a = 9 xx 10^(-3) kg//m^(2)) is

    A wave pulse starts propagating in the x direction along a non uniform wire of length 10m with mass per unit length is given by mu = mu_0 + ax and under a tension of 100N. The time taken by a pulse to travel from the lighter end to heavier end (mu_0 = 10^(-2) kg//m " and " a = 9 xx 10^(-3) kg//m^2) is

    A uniform rope having some mass hangs vertically from a rigid support. A transverse wave pulse is produced at the lower end. The speed (v) of the wave pulse varies with height (h) from the lower end as:

    A uniform rope of mass M length L hangs vertically from the ceiling, with lower end free. A distbance on the rope trvelling upwards starting from the lower end has a velocity v. At a point P at distance x from the lower end.